- Find the perimeter of a polygon and tell perimeter and area apart
- Convert units of area (mm², cm², dm², m², ares, hectares, km²)
- Derive and apply the area formulas of the rectangle, square, parallelogram, triangle, rhombus and trapezoid
- Find the area of composite shapes by splitting or completing them, and solve home-repair problems
Elvin's family wants to lay laminate flooring in a 5 m by 4 m room and fit skirting boards along the bottom of the walls. The amount of laminate depends on the room's area, and the length of skirting on its perimeter. Mix the two up and you either waste money or run back to the shop halfway through the job. In this lesson you will learn to tell perimeter and area apart, convert units of area, and use the area formulas of the main polygons — not by memorising them, but by seeing where each one comes from.
Perimeter
The sum of the lengths of all the sides of a polygon, that is, the length of its boundary. Perimeter is measured in units of length: mm, cm, dm, m, km. It is usually denoted by P.
You need no special formula for a perimeter — adding up all the sides is enough. But when sides are equal, the adding turns into multiplying and gives short formulas. A rectangle has two lengths and two widths, a square has four equal sides, and a regular polygon (one whose sides and angles are all equal) with n sides has n equal sides.
- a₁, a₂, …, aₙthe sides of any polygon
- 2(a + b)rectangle: a is the length, b the width
- 4asquare: a is the side
- n · aregular polygon: n is the number of sides, a the side
The perimeter of any polygon is the sum of its sides; the other three formulas are shortcuts for equal sides.
1) Find the perimeter of a triangle with sides 5 cm, 7 cm and 9 cm.
2) Find the perimeter of a rectangular yard 12 m long and 7.5 m wide.
3) A regular hexagon has sides of 4 cm. Find its perimeter.
4) A square has a perimeter of 36 cm. Find its side.
5) A rectangle has a perimeter of 30 cm and a length of 9 cm. Find its width.
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2) P = 2(12 + 7.5) = 2 · 19.5 = 39 m.
3) Six equal sides: P = 6 · 4 = 24 cm.
4) Since P = 4a, a = P ÷ 4 = 36 ÷ 4 = 9 cm.
5) Half the perimeter is a + b = 30 ÷ 2 = 15 cm, so the width is b = 15 − 9 = 6 cm. Check: 2(9 + 6) = 30 ✓
Area and units of area
The measure of how much flat surface a figure covers: the number of unit squares (squares with side 1) that fit inside it. Area is measured in square units: 1 cm² is the area of a square with 1 cm sides. It is usually denoted by A (some textbooks write S).
Every area formula rests on two simple properties of area. First, congruent figures have equal areas: if you cut a figure up and rearrange the pieces, the area does not change. Second, if a figure is split into several parts, its area is the sum of the areas of the parts. Below we derive every formula from the rectangle using exactly these two properties.
When the unit of length grows 10 times, both sides of the unit square grow 10 times, so the unit of area grows 10 · 10 = 100 times. For example, 1 dm = 10 cm, so 1 dm² holds 10 rows of 10 squares of 1 cm² each, that is 100 of them. Land has special units too: an are is the area of a square with 10 m sides, and a hectare is the area of a square with 100 m sides.
- a (are)the area of a square with 10 m sides: 10 m · 10 m = 100 m²
- hahectare — the area of a square with 100 m sides
- km²a square with 1 km = 1000 m sides: 1,000,000 m²
Neighbouring units of length differ by a factor of 10, neighbouring units of area by a factor of 100. Going to a smaller unit, multiply; going to a larger unit, divide.
1) Convert 3.5 m² to cm².
2) Convert 2400 cm² to m².
3) How many m² are there in 7 ha? How many ares?
4) A field measures 250 m by 400 m. Give its area in hectares.
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2) We go from a smaller unit to a larger one, so we divide: 2400 ÷ 10,000 = 0.24 m².
3) 7 ha = 7 · 10,000 = 70,000 m². Since 1 a = 100 m², that is 70,000 ÷ 100 = 700 ares.
4) A = 250 · 400 = 100,000 m²; 100,000 ÷ 10,000 = 10 ha.
Rectangle, square and parallelogram
Cover a 5 cm by 3 cm rectangle with 1 cm² squares: 5 squares in each row, 3 rows — 5 · 3 = 15 squares. So the area is 15 cm². The same reasoning works for any sides (for fractional ones too: then we count smaller squares, for example mm²). A square is a rectangle with equal sides, so its area is a · a = a². That is also why the second power of a number is called its “square”.
- a, badjacent sides of the rectangle (length and width), in the same unit
- athe side of the square (second formula)
The area of a rectangle is the product of two adjacent sides; the area of a square is its side squared.
1) Find the area of a rectangle with sides 8 cm and 5 cm.
2) Find the area of a square with sides of 1.2 m.
3) A rectangular room has an area of 60 m² and one side of 7.5 m. Find the other side and the perimeter.
4) A square has a perimeter of 28 cm. Find its area.
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2) A = 1.2² = 1.2 · 1.2 = 1.44 m².
3) b = A ÷ a = 60 ÷ 7.5 = 8 m; P = 2(7.5 + 8) = 31 m.
4) First the side: a = 28 ÷ 4 = 7 cm, then A = 7² = 49 cm².
Perimeter and area do not determine each other. Murad has 20 m of fencing and wants to fence off a rectangular vegetable patch. In every option the perimeter is 20 m, yet the area changes a lot:
| Sides | Perimeter | Area |
|---|---|---|
| 1 m × 9 m | 20 m | 9 m² |
| 2 m × 8 m | 20 m | 16 m² |
| 3 m × 7 m | 20 m | 21 m² |
| 4 m × 6 m | 20 m | 24 m² |
| 5 m × 5 m | 20 m | 25 m² |
Now the parallelogram. Drop the height BH from vertex B to the base AD. It cuts off the right triangle ABH. Move this triangle to the other end, next to side DC, and you get the rectangle HBCK with sides a and h. Nothing was lost and nothing was added, so the areas are equal: A = a · h. The height of a parallelogram is the distance between two opposite sides; the slanted side does not affect the area.
- aa side of the parallelogram (the base)
- hthe height drawn to that side — the distance between it and the opposite side
Any side can serve as the base, as long as the height is drawn to that very side: A = a · h₁ = b · h₂.
1) A side of a parallelogram is 12 cm and the height to it is 5 cm. Find the area.
2) A parallelogram has sides of 10 cm and 6 cm, and the height to the longer side is 3 cm. Find the area and the height to the shorter side.
3) A parallelogram has an area of 48 cm² and one side of 8 cm. Find the height to this side.
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2) A = 10 · 3 = 30 cm². Write the same area using the shorter side: 6 · h₂ = 30, so h₂ = 30 ÷ 6 = 5 cm. (A height cannot be longer than the adjacent side: 3 < 6 and 5 < 10 ✓)
3) h = A ÷ a = 48 ÷ 8 = 6 cm.
Triangle, rhombus and trapezoid
Take a congruent copy of any triangle ABC, turn it through 180° and attach it along side BC. Together the two congruent triangles form the parallelogram ABDC with base a and height h. The area of the parallelogram is a · h, and the triangle is exactly half of it. In a right triangle this is even easier to see: it is half of a rectangle whose sides equal the legs, cut along its diagonal.
- aany side of the triangle (the base)
- hthe height from the opposite vertex to that side (or to its extension)
In a right triangle each leg is the height to the other leg, so A = ½ · a · b (a and b are the legs).
1) Find the area of a triangle with base 8 cm and height 5 cm.
2) A right triangle has legs of 6 cm and 8 cm and a hypotenuse of 10 cm. Find the area and the height to the hypotenuse.
3) An obtuse triangle has a base of 7 cm; the height to this side falls outside the triangle and is 4 cm. Find the area.
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2) The legs are perpendicular: A = ½ · 6 · 8 = 24 cm². The same area through the hypotenuse: ½ · 10 · h = 24, so h = 48 ÷ 10 = 4.8 cm.
3) The formula works even when the height falls outside: A = ½ · 7 · 4 = 14 cm².
As you know from the lesson “Quadrilaterals: parallelogram, rectangle, rhombus, square and trapezoid”, the diagonals of a rhombus are perpendicular and bisect each other. Draw lines through the vertices of the rhombus parallel to the diagonals: you get a rectangle with sides d₁ and d₂. The diagonals split it into 8 congruent right triangles, and 4 of them lie inside the rhombus. So the rhombus is exactly half of that rectangle: A = ½ · d₁ · d₂. A rhombus is also a parallelogram, so A = a · h holds as well.
- d₁, d₂the diagonals of the rhombus
This formula holds for every convex quadrilateral with perpendicular diagonals: a rhombus, a square (A = d²/2), a kite.
1) A rhombus has diagonals of 10 cm and 24 cm and a side of 13 cm. Find its area and its height.
2) A square has a diagonal of 6 cm. Find its area.
3) A rhombus has an area of 96 cm² and one diagonal of 16 cm. Find the other diagonal.
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2) A square is a rhombus too: A = ½ · 6 · 6 = 18 cm². (Check: the side squared is a² = 18, so the area is 18 cm² ✓)
3) ½ · 16 · d₂ = 96, 8 · d₂ = 96, d₂ = 12 cm.
Split the trapezoid by the diagonal AC into two triangles. Triangle ACD has base AD = a, and triangle ABC has base BC = b. Their heights are the same — the height h of the trapezoid, because the bases are parallel. Add the areas: A = ½ · a · h + ½ · b · h = (a + b)/2 · h. The expression (a + b)/2 is the midline of the trapezoid, so in short A = m · h.
- a, bthe bases (parallel sides) of the trapezoid
- hthe height — the distance between the bases
- mthe midline: m = (a + b)/2
The area of a trapezoid is the average of its bases times its height.
1) Find the area of a trapezoid with bases 10 cm and 6 cm and height 4 cm.
2) A trapezoid has a midline of 9 cm and a height of 5 cm. Find the area.
3) A trapezoid has an area of 84 cm² and bases of 9 cm and 15 cm. Find the height.
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2) A = m · h = 9 · 5 = 45 cm².
3) The midline is m = (9 + 15)/2 = 12 cm, so h = A ÷ m = 84 ÷ 12 = 7 cm.
| Shape | Area | Perimeter |
|---|---|---|
| Rectangle (a, b) | A = a · b | P = 2(a + b) |
| Square (a) | A = a² | P = 4a |
| Parallelogram (a, b, h) | A = a · h | P = 2(a + b) |
| Triangle (a, b, c, h) | A = ½ · a · h | P = a + b + c |
| Rhombus (a, d₁, d₂) | A = ½ · d₁ · d₂ = a · h | P = 4a |
| Trapezoid (a, b, c, d, h) | A = (a + b)/2 · h | P = a + b + c + d |
Composite shapes and home-repair problems
Rooms, plots of land and machine parts are rarely simple shapes. Then we use the second property of area: we split the shape into familiar pieces, or complete it to a large rectangle and subtract the extra part. Both ways must give the same answer — which is also a good check.
- 11. Draw it and label the lengths
Mark the length of every side on the drawing. Find missing sides as the difference or the sum of opposite sides.
- 22. Split or complete
Split the shape into rectangles, triangles and trapezoids, or draw the rectangle around it and mark the pieces that are missing.
- 33. Find the area of each piece
Apply the right formula; all lengths must be in the same unit.
- 44. Add or subtract
When splitting, add the areas; when completing, subtract the missing pieces from the area of the large rectangle.
- 55. Check
Check the answer by the other method and make sure the unit is a square unit. Count the perimeter separately, along the boundary.
Find the area of the L-shaped room in the drawing in two ways. Also work out the perimeter for the skirting boards.
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Completing: 6 · 5 − 2 · 2 = 30 − 4 = 26 m² ✓
Perimeter, along the boundary: 4 + 2 + 2 + 3 + 6 + 5 = 22 m. That equals the perimeter of the 6 m × 5 m rectangle: 2(6 + 5) = 22 — the step-shape shortcut works.
The room is 5 m × 4 m and 2.7 m high; the door is 0.9 m wide and 2 m high, and the window measures 1.5 m × 1.2 m.
1) There is no skirting across the doorway. Skirting is sold in 2.5 m pieces. How many pieces are needed?
2) One pack of laminate covers 2.4 m². How many packs must be bought?
3) The walls get two coats of paint, and 1 litre covers 9 m² in one coat. How many litres are needed?
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2) A = 5 · 4 = 20 m²; 20 ÷ 2.4 ≈ 8.33. Eight packs (19.2 m²) are not enough — 9 packs.
3) “Unroll” the walls: they form a rectangle whose length is the perimeter and whose height is the room height: 18 · 2.7 = 48.6 m². Door and window: 0.9 · 2 + 1.5 · 1.2 = 1.8 + 1.8 = 3.6 m². Area to paint: 48.6 − 3.6 = 45 m², two coats — 90 m²; 90 ÷ 9 = 10 litres.
A bathroom floor is a 2.4 m × 1.8 m rectangle. It will be covered with 30 cm × 30 cm tiles. How many tiles are needed? How many must be bought with a 10% reserve for cutting and breakage?
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Check with areas: 2.4 · 1.8 = 4.32 m², one tile is 0.3 · 0.3 = 0.09 m², 4.32 ÷ 0.09 = 48 ✓
With the reserve: 48 · 1.1 = 52.8, so 53 tiles.
- 1.A square with 7 cm sides has an area of cm².
- 2.2.5 m² = cm²
- 3.A triangle with base 12 cm and height 5 cm has an area of cm².
- 4.A rhombus with diagonals of 8 cm and 11 cm has an area of cm².
- 5.A trapezoid with bases 5 cm and 9 cm and height 6 cm has an area of cm².
In this lesson we derived every area formula from a single rectangle. In the lesson “The Pythagorean theorem” you will see the famous link between the areas of the squares built on the sides of a right triangle, and circles are studied in the lesson “Circumference and area of a circle” — where the area of a disc also comes from the parallelogram formula.
Key points
- Perimeter is the length of the boundary (cm, m), area is the space covered (cm², m²); shapes with the same perimeter can have different areas.
- Neighbouring units of area differ 100 times: 1 m² = 10,000 cm², 1 a = 100 m², 1 ha = 10,000 m².
- Rectangle: A = a · b; square: A = a²; parallelogram: A = a · h.
- Triangle: A = ½ · a · h; rhombus: A = ½ · d₁ · d₂; trapezoid: A = (a + b)/2 · h = m · h.
- The height is perpendicular to the base — a slanted side is not the height.
- Find the area of a composite shape by splitting it or by completing it and subtracting; each method checks the other.
Check yourself
12 questions. Every correct answer earns XP.