- Measure angles with a protractor, classify them and calculate with the angle bisector
- Find unknown angles using the properties of adjacent and vertical angles
- Recognise the angle pairs formed by parallel lines and a transversal, and use their properties and the tests for parallel lines
- Calculate the angle between the hands of a clock at any time
A straight road crosses a railway at a slant. The two rails are parallel, the road cuts both of them, and eight angles appear at the crossings. Does an engineer have to measure all eight? No — just one. The other seven follow from the rules in this lesson. We start with the angle itself, then study the angles made by intersecting and parallel lines. In the next lesson, “Triangles”, these facts will prove that the angles of a triangle add up to 180°.
The angle: measuring and classifying
A figure made of two rays that start from the same point. The point is the vertex of the angle and the rays are its sides. An angle with vertex O and points A and B on its sides is written ∠AOB, or simply ∠O (the vertex letter goes in the middle).
Angles are measured in degrees. An angle whose sides form a straight line is a straight angle; split it into 180 equal parts and each part is 1°. A full turn is 360°. For more precision a degree is split into 60 minutes: 1° = 60′, so 37.5° = 37°30′. To measure an angle with a protractor:
- 1Centre on the vertex
Put the centre mark of the protractor on the vertex of the angle.
- 2Zero line along a side
Line up the zero line of the protractor with one side of the angle.
- 3The right scale
Read the number where the other side crosses the scale, using the scale that starts at 0 on the first side.
- 4Check by eye
If the angle looks acute, the answer must be less than 90°: reading 130° instead of 50° is the most common mistake.
| Type of angle | Size |
|---|---|
| Acute angle | 0° < α < 90° |
| Right angle | α = 90° |
| Obtuse angle | 90° < α < 180° |
| Straight angle | α = 180° |
The ray from the vertex of an angle that divides it into two equal angles.
- ∠AOBthe whole angle
- OCa ray inside the angle; the bisector splits it into two equal parts
A ray inside an angle splits it into two angles that add up to the whole angle. The bisector splits it exactly in half.
1) Ray OC bisects ∠AOB, and ∠AOB = 76°. Find ∠AOC.
2) Ray OC lies inside ∠AOB = 132°, and ∠AOC is 3 times ∠COB. Find both angles.
3) Into which angles does the bisector split a 75° angle? Give the answer in degrees and minutes.
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2) Let ∠COB = x; then ∠AOC = 3x. Adding the angles: 3x + x = 132°, 4x = 132°, x = 33°.
Answer: ∠COB = 33°, ∠AOC = 99°. Check: 99° + 33° = 132°.
3) 75° ÷ 2 = 37.5°. 0.5° = 0.5 · 60′ = 30′, so each angle is 37°30′.
Adjacent and vertical angles. Perpendicular lines
Two angles that share one side, while their other two sides are opposite rays (they continue each other along one line). Together they form a straight angle.
- α, βadjacent angles (a linear pair)
Adjacent angles add up to 180° because together they fill a straight angle. So the angle next to an acute angle is obtuse, and the angle next to a right angle is also right.
1) One of two adjacent angles is 35°. Find the other.
2) One of two adjacent angles is 40° larger than the other. Find both angles.
3) Two adjacent angles are in the ratio 2 : 7. Find them.
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2) Let the smaller angle be x; then the larger is x + 40°. x + x + 40° = 180°, 2x = 140°, x = 70°.
Answer: 70° and 110°.
3) Let the angles be 2k and 7k: 2k + 7k = 180°, 9k = 180°, k = 20°.
Answer: 40° and 140°. Check: 40° + 140° = 180°.
Two angles such that the sides of one are the extensions of the sides of the other. Two intersecting lines form two pairs of vertical angles.
- ∠1 and ∠3; ∠2 and ∠4the two pairs of vertical angles
Vertical angles are equal.
Why? Each of ∠1 and ∠3 is adjacent to ∠2. So ∠1 = 180° − ∠2 and ∠3 = 180° − ∠2, which means ∠1 = ∠3. In the same way ∠2 = ∠4. So knowing one of the four angles at a crossing is enough: its vertical angle is equal to it, and the other two are adjacent to it.
1) Two lines cross, and one of the angles is 58°. Find the other three.
2) Two lines cross, and two of the four angles add up to 100°. Find all four angles.
3) Two lines cross, and one of the angles is 4 times another. Find all four angles.
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2) Two adjacent angles would add up to 180°, but these add up to 100°. So they are vertical angles and are equal: each is 100° ÷ 2 = 50°. The other two are 180° − 50° = 130°.
3) The two angles are not equal, so they cannot be vertical — they are adjacent: x + 4x = 180°, x = 36°.
Answer: 36°, 144°, 36°, 144°.
Two lines that meet at a right angle; we write a ⊥ b. All four angles they form are 90°.
Why are all four angles right? The angle next to a 90° angle is 180° − 90° = 90°, and vertical angles are equal. Through any point of the plane there is exactly one line perpendicular to a given line. The length of the perpendicular dropped from a point to a line is the distance from the point to the line — it is the shortest of all segments joining the point to points of the line.
Parallel lines and a transversal
Two lines in one plane that never meet; we write a ∥ b. Parallel postulate: through a point not on a line there is exactly one line parallel to it.
A line that crosses two other lines is called a transversal. When the transversal c crosses lines a and b, four angles appear at each crossing — eight in total. Angles 3, 4, 5 and 6, which lie between a and b, are interior; angles 1, 2, 7 and 8 are exterior. The names of the angle pairs describe where the angles are:
- Corresponding angles are in the same position at each crossing: 1 and 5, 2 and 6, 3 and 7, 4 and 8.
- Alternate interior angles are interior and on opposite sides of the transversal: 3 and 5, 4 and 6 (the alternate exterior angles are 1 and 7, 2 and 8).
- Co-interior angles (same-side interior angles) are interior and on the same side of the transversal: 3 and 6, 4 and 5.
- ∠1, ∠5corresponding angles (equal)
- ∠3, ∠5alternate interior angles (equal)
- ∠3, ∠6co-interior angles (sum 180°)
Properties of the angles formed by parallel lines and a transversal: corresponding angles are equal, alternate interior angles are equal, and co-interior angles add up to 180°. The same holds for the other pairs.
Why? Parallel lines have the same direction: if you slide line b along c until it lies on a, the “cross” at the lower crossing becomes an exact copy of the upper one — that is why corresponding angles are equal. (In a geometry course this fact is proved strictly from the parallel postulate.) The other two properties follow from it: ∠3 = ∠7 (corresponding) and ∠7 = ∠5 (vertical), so ∠3 = ∠5. And ∠6 is adjacent to ∠5, so ∠3 + ∠6 = ∠5 + ∠6 = 180°.
As in the figure, a ∥ b and c is a transversal.
1) ∠2 = 56°. Find all eight angles.
2) One co-interior angle is 50° larger than the other. Find them.
3) One of the eight angles is 3 times another. Find these angles.
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Answer: ∠2 = ∠4 = ∠6 = ∠8 = 56°, ∠1 = ∠3 = ∠5 = ∠7 = 124°.
2) Co-interior angles add up to 180°: x + x + 50° = 180°, x = 65°.
Answer: 65° and 115°.
3) Two unequal angles here are an acute and an obtuse one, and they add up to 180°: x + 3x = 180°, x = 45°.
Answer: 45° and 135°.
Tests for parallel lines
The reverse question matters too: how can we tell from the angles that two lines are parallel? After all, we cannot extend the lines forever and check that they never meet. The properties also work in reverse — these are the tests for parallel lines.
- a, btwo lines
- ∠1, ∠3, ∠5, ∠6angles formed with the transversal c (numbered as in the figure)
Tests for parallel lines: if corresponding angles are equal, or alternate interior angles are equal, or co-interior angles add up to 180°, the lines are parallel. Any one of the three conditions is enough.
Proof (for alternate angles). Let ∠3 = ∠5. Through the point where a meets c draw the line a′ parallel to b; by the parallel postulate there is only one such line. Since a′ ∥ b, the alternate interior angle between a′ and c equals ∠5, that is ∠3. So a and a′ leave that point on the same side of c at the same angle — they coincide. Hence a = a′, i.e. a ∥ b. The other two tests reduce to this one: equal corresponding angles give equal alternate angles through vertical angles, and co-interior angles adding up to 180° give the same through adjacent angles.
- Two lines perpendicular to the same line are parallel: the co-interior angles are 90° + 90° = 180°.
- Two lines parallel to a third line are parallel to each other: otherwise two parallels to the third line would pass through their common point, which contradicts the postulate.
The transversal c crosses lines a and b (numbered as in the figure). In each case decide whether a ∥ b.
1) ∠4 = 47°, ∠6 = 47°.
2) ∠3 = 118°, ∠6 = 72°.
3) ∠1 = 125°, ∠8 = 55°.
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2) ∠3 and ∠6 are co-interior angles: 118° + 72° = 190° ≠ 180°, so a and b are not parallel. On the other side of the transversal the co-interior angles add up to (180° − 118°) + (180° − 72°) = 62° + 108° = 170° < 180°; that is the side where the lines meet.
3) ∠8 = 55°, so the adjacent angle ∠5 = 180° − 55° = 125°. ∠1 = ∠5 = 125° — the corresponding angles are equal, so a ∥ b.
a ∥ b. Point A is on a, point B is on b, and point M lies between the parallel lines (see the figure). The angle between line a and segment AM is 40°, and the angle between line b and segment BM is 35°. Find ∠AMB.
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2) a ∥ MK with transversal AM: ∠KMA = 40° (alternate interior angles).
3) b ∥ MK with transversal BM: ∠KMB = 35° (alternate interior angles).
4) ∠AMB = ∠KMA + ∠KMB = 40° + 35° = 75°.
Rule: in such a zigzag the middle angle equals the sum of the two outer angles.
The angle between the hands of a clock
Clock problems are good practice with angles. A clock face is divided into 12 equal parts of 360° ÷ 12 = 30° each. The minute hand makes a full turn in 60 minutes, so it turns 360° ÷ 60 = 6° per minute. The hour hand turns 30° per hour, which is only 30° ÷ 60 = 0.5° per minute. At time h:m the minute hand has turned 6m degrees from 12, and the hour hand 30h + 0.5m degrees. The angle between the hands is the difference of these two numbers.
- hhours (0 to 11; for times after 12:00 use h = 0)
- mminutes (0–59)
- θthe angle between the hands; if it comes out larger than 180°, take 360° − θ
Where it comes from: (30h + 0.5m) − 6m = 30h − 5.5m. Every minute the minute hand gains 6° − 0.5° = 5.5° on the hour hand.
Find the angle between the hands at: 1) 4:00; 2) 2:30; 3) 9:45; 4) 12:40.
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2) θ = |30° · 2 − 5.5° · 30| = |60° − 165°| = 105°. The hour hand is exactly halfway between 2 and 3, so the answer is not 4 · 30° = 120°.
3) θ = |30° · 9 − 5.5° · 45| = |270° − 247.5°| = 22.5° = 22°30′.
4) h = 0: θ = |0 − 5.5° · 40| = 220° > 180°, so the smaller angle is 360° − 220° = 140°.
1) When do the hands first meet after 3:00?
2) At 12:00 the hands are together. When does this happen next?
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Answer: at about 3:16:22.
2) The minute hand has to gain a full turn, 360°: 360° ÷ 5.5° = 65 5/11 minutes ≈ 1 h 5 min 27 s.
Answer: at about 1:05:27. So the hands meet 11 times in 12 hours.
- 1.The angle adjacent to a 35° angle is °.
- 2.Two lines cross and one angle is 72°. Its vertical angle is °.
- 3.a ∥ b, and one co-interior angle is 64°. The other is °.
- 4.The bisector splits a 130° angle into two angles of °.
- 5.At 5:00 the angle between the hands is °.
Key points
- An acute angle is less than 90°, a right angle is 90°, an obtuse angle is between 90° and 180°, a straight angle is 180°; 1° = 60′.
- A bisector halves an angle; adjacent angles add up to 180°, vertical angles are equal.
- Perpendicular lines form four right angles; the distance from a point to a line is the length of the perpendicular.
- If a ∥ b, corresponding and alternate interior angles are equal, and co-interior angles add up to 180°.
- If any one of these three conditions holds, the lines are parallel; two lines perpendicular to the same line are parallel.
- The angle between the clock hands is θ = |30° · h − 5.5° · m|; if it is more than 180°, take 360° − θ.
Check yourself
12 questions. Every correct answer earns XP.